Level 3 Integration Walkthrough
2017 NCEA Level 3 Integration Question 2(c)
2017 Paper
Question
The diagram below shows the curve \(y=-x^2+3x+10\), and the line \(y=-x+14\), which is the tangent to the curve at the point \((2,12)\).
Calculate the shaded area.
You must use calculus and show the results of any integration needed to solve the problem.
The diagram is shown in its initial state. JavaScript adds any interactive controls and later walkthrough visuals.
First walkthrough idea
Focus to try first
Treat the shaded region as the area under the tangent from \(2\) to \(14\), minus the area under the parabola from \(2\) to \(5\).
Step 1
Split the shaded region
The source construction uses one large area under the tangent, then removes the area under the parabola.
Show the first step’s working
The shaded area is equal to the area under the tangent from \(x=2\) to \(x=14\), minus the area under the parabola from \(x=2\) to \(x=5\).
Walkthrough overview
What this question practises
This 2017 walkthrough is part of AS91579 — Apply integration methods in solving problems.
Method: Finding the shaded area between a parabola and its tangent.
This is Question 2(c) from the 2017 NCEA Level 3 Integration paper for AS91579 — Apply integration methods in solving problems. Use the guided hints to practise the method before revealing the full working.
Calc.nz is an independent learning resource. Compare questions, diagrams, and assessment information with the official NZQA resources for AS91579.
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Learning summary
Review the method, not only the answer
This walkthrough helps you practise finding the shaded area between a parabola and its tangent. Use the hints to plan the method, then repeat the question without hints and check each step.
Common mistake to avoid
Check intersections, signs, and whether the question asks for signed area or total geometric area.