Level 3 Integration Walkthrough

2019 NCEA Level 3 Integration Question 1(e)

2019 Paper

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Question

Question 1(e) original exam prompt; text transcription follows

The rate of change of quantity \(N\) at any instant is given by the differential equation \(\frac{dN}{dt}=kN\).

If \(N\) has positive values \(N_1\) and \(N_2\) at times \(t_1\) and \(2t_1\), respectively, prove that \(k=\frac{1}{t_1}\ln\!\left(\frac{N_2}{N_1}\right)\).

You must use calculus and show the results of any integration needed to solve the problem.

First walkthrough idea

Focus to try first

Separate the differential equation, integrate logarithmically, then compare the two given positive values of \(N\).

Step 1

Separate and integrate

Move \(N\) to the left and \(dt\) to the right.

Show the first step’s working
\[ \frac{dN}{dt}=kN \] \[ \frac{1}{N}\,dN=k\,dt \] \[ \int N^{-1}\,dN=\int k\,dt \] \[ \ln|N|=kt+C \]

Walkthrough overview

What this question practises

This 2019 walkthrough is part of AS91579 — Apply integration methods in solving problems.

Method: Proving an exponential-growth relation from a differential equation.

This is Question 1(e) from the 2019 NCEA Level 3 Integration paper for AS91579 — Apply integration methods in solving problems. Use the guided hints to practise the method before revealing the full working.

Calc.nz is an independent learning resource. Compare questions, diagrams, and assessment information with the official NZQA resources for AS91579.

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Learning summary

Review the method, not only the answer

This walkthrough helps you practise proving an exponential-growth relation from a differential equation. Use the hints to plan the method, then repeat the question without hints and check each step.

Common mistake to avoid

Check each step against the original condition, preserve signs and restrictions, and confirm that the final result answers the question asked.

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